Chem 103 chemistry Study guides, Class notes & Summaries
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CHEM 103 Module 1 to 6 Exam Questions and Answers (Portage Learning)
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CHEM 103 Module 1 to 6 Exam Questions and Answers (Portage Learning) Show the calculation of the mass of a 18.6 ml sample of freon with 
density of 1.49 g/ml 
2. Show the calculation of the density of crude oil if 26.3 g occupies 30.5 
ml. 
1. M = D x V = 1.49 x 18.6 = 27.7 g 
2. D = M / V = 26.3 / 30.5 = 0.862 g/ml 
Question 5 
Click this link to access the Periodic Table. This may be helpful throughout 
the exam. 
1. 3.0600 contains ? significant figures. 
2. 0.0151 contains ? significant figu...
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CHEM 103 Lab Exam 8 – Portage Learning
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CHEM 103 Lab Exam 8 – Portage Learning. Why was warming data used for estimating the freezing/melting 
point of the cyclohexane? 
3. (3 points) How much of the cyclohexane solvent was placed in the test? 
1.) molarity 
2.) It is considered reliable. 
It is a dependable predicator of the freezing/melting point of a substnace. 
it can determine the temperatures when the change occurs.
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CHEM 103 Lab Exam 5 – Portage Learning
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CHEM 103 Lab Exam 5 – Portage Learning . According to Boyle’s law, as the volume of a gas decreases, the 
pressure _________. 
3. (6 points) A sample of gas occupies a volume of 10.5 L when the pressure 
is 14.3 psi. Use Boyle’s Law to calculate the volume (L) when the pressure is 
decreased to 12.8psi. Show the calculation. 
Answer: 
1. A syringe was used, and the volume was read from the graduation 
markings.
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CHEM 103 Module 1 to 6 Exam Questions and Answers (Portage Learning)
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CHEM 103 Module 1 to 6 Exam Questions and Answers (Portage Learning) Using the following information, do the conversions shown below, showing all 
work: 
1 ft = 12 inches 1 pound = 16 oz 1 gallon = 4 quarts 
1 mile = 5280 feet 1 ton = 2000 pounds 1 quart = 2 pints 
kilo (= 1000) milli (= 1/1000) centi (= 
1/100) deci (= 1/10) 
1. 24.6 grams = ? kg 
2. 6.3 ft = ? inches 
1. 24.6 grams x 1 kg / 1000 g = 0.0246 kg 
2. 6.3 ft x 12 in / 1 ft = 75.6 inches 
please always use the correct units in your ...
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CHEM 103 Lab Exam 4 – Portage Learning
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CHEM 103 Lab Exam 4 – Portage Learning. Does the following reaction give off heat or absorb heat? 
Explain briefly. 
C D H = +263Kcal/mol 
3. (4 points) In one experiment in the video, room temperature water was 
mixed with water at about 38 degrees. To what temperature (about) did the 
mixture of the two water samples come to after setting for a few minutes? 
Answer: 
1. The heat depends on the amount of substance. If the amount of substance 
is doubled, then the heat doubles. Other propertie...
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Portage Learning: CHEM 103 Final Exam (2 Versions) & CHEM 103 Module 1, 2, 3, 4, 5, 6, 7 Exam (2 Versions of Each Exam) (Latest-2023): General Chemistry II |100% Correct Q & A|
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Portage Learning: CHEM 103 Final Exam (2 Versions) & CHEM 103 Module 1, 2, 3, 4, 5, 6, 7 Exam (2 Versions of Each Exam) (Latest-2023): General Chemistry II |100% Correct Q & A|
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CHEM 103 Chemistry Module 1, 2, 3, 4, 5, 6 Exam (Latest-2022)/ CHEM103 Chemistry Module 1, 2, 3, 4, 5, 6 Exam: Portage Learning |Verified Q & A|
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CHEM 103 Chemistry Module 1, 2, 3, 4, 5, 6 Exam (Latest-2022)/ CHEM103 Chemistry Module 1, 2, 3, 4, 5, 6 Exam: Portage Learning |Verified Q & A|
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CHEM 103 Chemistry Lab Report 4 (100% Correct Answers) Portage Learning | Download To Score An A
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CHEM 103 Chemistry Lab Report 4 (100% Correct Answers) Portage Learning | Download To Score An A
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CHEM 103 Lab Exam 3 – Portage Learning
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CHEM 103 Lab Exam 3 – Portage Learning. A 1.1000 gram hydrate sample chosen from Na2CO3∙10H2O, AlCl3∙6H2O, 
MgCl2∙6H2O and BaCl2∙2H2O was heated and found to lose 0.5841 gram of H2O. (1) 
Show the calculation of the % H2O in the unknown hydrate sample. (2) Show the 
calculation of the % H2O in each of the hydrate compounds and identify the unknown 
hydrate from the list. 
Atomic weights: H = 1.008, O = 16.00. MWs: Na2CO3∙10H2O = 286.15, AlCl3∙6H2O = 
241.43, MgCl2∙6H2O = 203.301 ...
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CHEM 103 Chemistry Lab Report 2 | 100 OUT OF 100 | Portage Learning.
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CHEM 103 Chemistry Lab Report 2 | 100 OUT OF 100 | Portage Learning.